Calculate ΔE, if a system releases 66.3 kJof heat to its surroundings while the surroundings do 43.0 kJ of work on the system.
Express your answer using two significant figures.
ΔEΔE =____________ kJ
By first law of thermodynamics
= q + w
Heat is released by the system hence q is negative.
So, q = - 66.3 KJ.
Work done onto the system , hence w is positive.
So, w = 43.0 KJ
Now, = (- 66.3 + 43.0) KJ = - 23.3 KJ.
Final answer is two significant figures is
= - 23 KJ.
Calculate ΔE, if a system releases 66.3 kJof heat to its surroundings while the surroundings do...
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