A system releases 425 J of heat and performs 425 J of work to its surroundings....
A system releases 425 J of heat and performs 425 J of work to its surroundings. What is the change in internal energy of the system in calories? Please show the steps
Homework Answers
Q = -425 J
W = - 425 J
Use:
delta E = Q + W
= -425 J - 425 J
= -850 J
= -850/4.184 cal
= -203 cal
Answer: -203 cal
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