Question

If a system has 2.50 x 10 kcal of work done to it, and releases 5.00 x 10' J of heat into its surroundings, what is the change in internal energy (AE or AU) of the system?

Answer 1

ou= Q tw D Q & heat energy Q tue if added to the system Q ue if į releases to surrounding 2 w) work w tue if w ave if world done on system work done by the system . I cal=4.1845

1 . Cal=4.lduu W = +2.50 8lo k [4.184 J =+1.046 xlo' KJ [ done on system) != -5.00 x 102 kJ [ released from system) Du = [1.046 X108 ks]+[-5.00 X10 ks) = 546 KJ" . Ans),- internal Eneday system =0 Glob) ou= change of the 54 6 kJ