If a system has 425 kcal of work done to it, and releases 5.00×102 kJ of...

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If a system has 425 kcal of work done to it, and releases 5.00×102 kJ of...

If a system has 425 kcal of work done to it, and releases 5.00×102 kJ of heat into its surroundings, what is the change in internal energy (Δ? or Δ?) of the system?

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Answer 1

Answer #1

W = 425 kcal
= 425*4.184 KJ
= 1778.2 KJ

Q = -500 KJ

Use;
Δ? = Q + W
= -500 KJ + 1778.2 KJ
= 1.28*10^3 KJ

Answer: 1.28*10^3 KJ

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Answer 2

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