If a system has 225 kcal of work done to it, and releases 5.00 × 10...

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If a system has 225 kcal of work done to it, and releases 5.00 × 10...

If a system has 225 kcal of work done to it, and releases 5.00 × 10 2 kJ of heat into its surroundings, what is the change in internal energy ( Δ E or Δ U ) of the system?

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Answer 1

Answer #1

W = +225 kcal
= +225 * 4.184 KJ
= 941.4 KJ

Q = -500 KJ [negative because heat is released]

Now use:
ΔU = Q + W
= -500 KJ + 941.4 KJ
= 441.4 KJ

Answer: 441 KJ

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Answer 2

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