Heat absorbed by water, q = mC∆T
C is the specific heat capacity of water = 4.186 J/g°C
So, q = 100×4.186×(26.4 - 22.1)
q = 100×4.186×4.3 J = 1799.98 J
Since, 1KJ = 1000J
q = 1799.98/1000 KJ = 1.799 KJ = 1.80 KJ
Now, heat released during dissolution of NaOH is equal to the heat absorbed by water.
i.e. ∆Hdiss = - q (negative sign because heat is released)
∆Hdiss= -1.80 KJ
Molar Mass of NaOH is 40 g/mol
2g NaOH release 1.80 KJ heat
40 g NaOH release 1.80×40/2 KJ = 36 KJ/mol
So, ∆Hdiss = - 36 KJ/mol
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