Problem 27.64 At the equator, the direction of Earth's magnetic field is horizontal and to the north, and the magnitude is 3.5 ×10−5T. |
Part A What is the magnetic flux through a circular loop of radius 0.30 m , lying flat on the ground at the equator?
SubmitRequest Answer Part B What is the magnetic flux through the loop of radius 0.30 m balanced on its edge on the ground at the equator, when the axis that runs perpendicular to the plane of the loop points northwest?
SubmitRequest Answer Part C What is the magnetic flux through the loop of radius 0.30 m balanced on its edge on the ground at the equator, when the axis that runs perpendicular to the plane of the loop is points due north?
SubmitRequest Answer Part D What is the magnetic flux through the loop of radius 0.30 m balanced on its edge on the ground at the equator, when the axis that runs perpendicular to the plane of the loop is points to the west?
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Area of the loop A= 0.32
= 0.28 n , n is perpendicular to the surface -
area vector
earth magnetic field B = 3.5e-5 T - North ward
flux =
B . A
A . when the the loop is lying flat on the surface of earth B and A are perpendicular , the dot product =0
flux =
BACos(90) =0
B. when the loop axis pointing NW angle between B and the area vector = 45 deg
= BA
Cos(45) = 3.5e-5 * 0.28 * Cos(45) = 7.0e-6 wb
C. when the loop pointing North, angle between the vectors =0
= BA
Cos(0) = 3.5e-5 * 0.28 Cos(0) = 9.8e-6 wb
D. When the loop is pointing WEST angle between the vector =90 deg
= BA
Cos(90) = 0
Problem 27.64 At the equator, the direction of Earth's magnetic field is horizontal and to the...
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