Question

1. Using Dev C++, write a program to solve the problem as stated below. Make use of a repetition structure (counter-controlled while loop) to shorten part of your code
2. Dont use array.
3. Write a program will input a single integer value (all input will be exactly 8 digits long) and will store pairs of digits as individual integer values. The program will display the five 2-digit numbers as well as the average of these, each on their own line. Use a switch statement to print out Grade: and then either A (>=90), B ([80..89]), C ([70..79]), D ([60..69]) or F (<60) based on the calculated average.
   1. Sample
      1. Input: 54861398
      2. Output:       

54

86

13

98

Avg: 62.75

Grade: D

2. Sample
   1. Input: 64536785
   2. Output:        

64

92

67

85

Avg: 77.00

Grade: D

3. make use of a repetition structure (counter-controlled while loop) to shorten part of your code.
4. Compile the program and correct errors.

Answer 1

Any Queries Comment Below

Happy Coding!!!

2. Sample
   1. Input: 64536785
   2. Output:        

64

92

67

85

Avg: 77.00

Grade: D ( Wrong answer) it should be C because (D[69-60] C[70-79) as per the question

C++ Code:

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#include <iostream>
using namespace std;
//Function to reverse the interger
int reverse(long int n)
{
long int r=0;
while(n!=0)
{
r = r*10+n%10;
n=n/10;
  
}
return r;
}
int main()
{
  
long int n,r=0,s=0,i=4,j;
float grade;
//reading input
std::cin >> n;
//reverseing the input
//54861398 into 98316845
r=reverse(n);
while(i!=0)
{
// r%100 == 45 and j ==54 for first time
j=reverse(r%100);
std::cout << j << std::endl;
s = s + j;
r = r/100;
i--;
}
//calculating average
grade = s/float(4);
//Displaying the aaverage value
printf("Avg: %.2f\n",grade);
//checking Grade base on the average and Displaying the correspondence grade
if(grade>=90)
std::cout << "Grade: A" << std::endl;
else if (grade>=80 and grade<=89)
std::cout << "Grade: B" << std::endl;
else if (grade>=70 and grade<=79)
std::cout << "Grade: C" << std::endl;
else if(grade>=60 and grade<=69)
std::cout << "Grade: D" << std::endl;
else
std::cout << "Grade: F" << std::endl;
return 0;
  
}
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