Question

Here is the skeleton of the password checking program. We have the character counting function (you will need to finish it), and a function to check if the password is good.

Change the password algorithm so that (three of the four) two uppercase, two lowercase, two digits, or one other is present. Also change the required length of the password to 10.

Bonus points for making the program loop until a good password is entered. You will need to read the new password inside the loop if the originally entered password is not good.

// string-character-count
#include <iostream>
#include <string>
using namespace std;
void characterCount(string text, int &upper, int &lower, int &number, int &other) {
   int count[256] = {};
   upper = lower = number = other = 0;
  
   for(int i=0;i<text.length();i++)
       count[text[i]] += 1;
  
   for (int c=48;c<58;c++)   // number digits
       number += count[c];
  
   // calculate upper count, lower count, and other count
  
   /*
   // this displays the count for each character
   for(int i=0;i<256;i++) {
       if (count[i] > 0)
           cout << i << "\t" << (char) i << "\t" << count[i] << endl;
   }
   */
}
bool isGoodPassword(string password) {
   int upper, lower, digit, other;
   int criteriaMet = 0;

   characterCount(password, upper, lower, digit, other);
   if (password.length() >= 8) {
       if (upper > 0) criteriaMet++;
       if (lower > 0) criteriaMet++;
       if (digit > 0) criteriaMet++;
       if (other > 0) criteriaMet++;
       if (criteriaMet >= 3)
           return true;
       else
           return false;
   } else
       return false;
}

int main() {
   string text;
   int upper, lower, number, other;
  
   cout << "Enter text:";
   getline(cin, text);
   characterCount(text, upper, lower, number, other);
   cout << "Upper:\t" << upper << "\tLower:\t" << lower
       << "\tNumber:\t" << number << "\tOther:\t" << other << endl;
   if (isGoodPassword(text)) {
       cout << "That is a good password!" << endl;
   } else {
       cout << "Not a good password, try again." << endl;
   }

}

Answer 1

#include <iostream>
#include <string>
using namespace std;
void characterCount(string text, int &upper, int &lower, int &number, int &other) {
int count[256] = {};
upper = lower = number = other = 0;
  
for(int i=0;i<text.length();i++){
if(text[i]>='A' && text[i]<='Z')
upper++;
else if(text[i]>='a' && text[i]<='z')
lower++;
else if(text[i]>='0' && text[i]<='9')
number++;
else
other++;
}
}
bool isGoodPassword(string password) {
int upper, lower, digit, other;
int criteriaMet = 0;

characterCount(password, upper, lower, digit, other);
if (password.length() >= 10) {
if (upper >=2) criteriaMet++;
if (lower >=2) criteriaMet++;
if (digit >=2 || other>=1) criteriaMet++;
if (criteriaMet >= 3)
return true;
else
return false;
} else
return false;
}

int main() {
string text;
int upper, lower, number, other;
while(true){
cout << "Enter text:";
getline(cin, text);
characterCount(text, upper, lower, number, other);
cout << "Upper:\t" << upper << "\tLower:\t" << lower
<< "\tNumber:\t" << number << "\tOther:\t" << other << endl;
if (isGoodPassword(text)) {
cout << "That is a good password!" << endl;
break;
} else {
cout << "Not a good password, try again." << endl;
}
}
}

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