In New England, the horizontal component of the Earth's magnetic field has a magnitude of 2.5 × 10-5 T. An electron is shot vertically straight up from the ground with a speed of 1.0 × 106 m/s. What is the magnitude of the acceleration caused by the magnetic force? Ignore the gravitational force acting on the electron.
In New England, the horizontal component of the Earth's magnetic field has a magnitude of 2.5...
In New England, the horizontal component of the Earth's magnetic field has a magnitude of 1.2 × 10-5 T. An electron is shot vertically straight up from the ground with a speed of 3.4 × 106 m/s. What is the magnitude of the acceleration caused by the magnetic force? Ignore the gravitational force acting on the electron.
At New York City, the earth's magnetic field has a vertical component of 5.20 × 10-5 T that points downward (perpendicular to the ground) and a horizontal component of 1.80 × 10-5 T that points toward geographic north (parallel to the ground). What is the magnitude of the magnetic force on a 4.13-m long, straight wire that carries a current of 14.3 A perpendicularly into the ground?
At a certain location, the horizontal component of the earth's magnetic field is 3.0 × 10-5 T, due north. A proton moves eastward with just the right speed, so the magnetic force on it balances its weight. Find the speed of the proton.
At New York City, the earth’s magnetic field has a vertical component of 5.20 × 10-5 T that points downward (perpendicular to the ground) and a horizontal component of 1.80 × 10-5 T that points toward geographic north (parallel to the ground). What is the magnitude of the magnetic force on a 7.71-m long, straight wire that carries a current of 21.2 A perpendicularly into the ground? Ans: 2.94 x 10-3N
#2 near the ground at the north magnetic pole, the earth’s magnetic field is directed downward vertically and has a strength of 0.57 G. An electron at the north pole is projected from the ground into this magnetic field with a velocity of 1.4 km/s vertically upward and 1.9 km/s horizontally to your right. A) find the magnitude of the force acting on this electron B) find the electron’s acceleration (magnitude and direction)
An electron travels toward the north in a region where the Earth's magnetic field has the magnitude 5.0x10^-5 T and is directed downward at 35 degrees below the horizontal. The magnitude of the force that the Earth's magnetic field exerts on the electron is 1.3x10^-18 N. What is the speed of the electron? A. 2.8x10^5 m/s B. 8.0x10^5 m/s C. 3.5x10^5 m/s D. 5.0x10^5 m/s E. 4.1x10^5 m/s
The aurora is caused when electrons and protons, moving in the earth's magnetic field of ≈5×10−5 T, collide with molecules of the atmosphere and cause them to glow. What is the radius of the circular orbit for (a) an electron with speed 1.0×106 m/s and (b) a proton with speed 7.0×104 m/s . Part A Express your answer using two significant figures.
In a certain region, the earth's magnetic field has a magnitude of 4.7 × 10-5 T and is directed north at an angle of 41° below the horizontal. An electrically charged bullet is fired north and 18° above the horizontal, with a speed of 630 m/s. The magnetic force on the bullet is 3.9 × 10-10 N, directed due east. Determine the bullet's electric charge, including its algebraic sign (+ or -).
Question 3:9 points Earth's Magnetic Field: The following data were recorded from the horizontal component of earth's magnetic field R: radius of the coil. N: Number of turns experiments. N 250 turns R 7.5 cm tan Bave I (mA) 2.5 4.2 9.5 14.2 25.5 16 34 45 62 16 32 45 60 a) Fill the table. (2 points) b) Use the data in the table to plot a graph between the current I and tan a (3 points) c) Determine...
A uniform 5.5 T magnetic field points north. If an electron moves vertically downward (to- ward the ground) with a speed of 3.1 × 107 m/s through this field. The charge on a proton is 1.60×10−19. a) What is the magnitude of the force acting on it? Answer in units of N.