Suppose that the volume of the lungs is V, the amount of breathed in and out is W, the initial concentration of chemical is c0, and the ambient concentration of chemical is γ. Given that V=2L, W=0.5L, c0=1mmol/L, γ=5mmol/L, find the following:
Step 1: The amount of chemical in the lungs before breathing is equal to
Step 2: The amount of chemical breathed out is equal to
Step 3: The amount of chemical in the lungs after breathing out is equal to
Step 4: The amount of chemical breathed in is equal to
Step 5: The amount of chemical in the lungs after breathing in is equal to
Step 6: The concentration of chemical in the lungs after breathing in is equal to
step 1
amount of chemical = concentration*volume
c0 = 1 mmol/L and volume,V = 2L
hence, amount of chemical = 1 mmol/L * 2 L = 2 mmol
Step 2
amount of chemical breathed out = Volume breathed out * c0
volume breathed out ,W = 0.5 L
so, amount of chemical breathed out = 0.5 L * 1 mmol/L = 0.5 mmol
Step 3
amount of chemical in the lungs after breathing out = (2-0.5) * c0
= 1.5 L * 1 mmol/L = 1.5 mmol
Step 4
The amount of chemical breathed in = γ* W
= 5 mmol/L * 0.5 = 2.5 mmol
Step 5
The amount of chemical in the lungs after breathing in = initial amount - amount breathed out + amount breathed in
= 2 mmol - 0.5 mmol + 2.5 mmol
= 4 mmol
Step 6
The concentration of chemical in the lungs after breathing in = total amount/ volume
= 4 mmol / 2 L
= 2 mmol/L
Suppose that the volume of the lungs is V, the amount of breathed in and out...
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How do you find the initial concentration if you are only
given the initial volume and final volume? I have tried using the
V(i) x C(i) =V(f) x C(f) equation but it needs at least 3 figures
so I'm a bit lost right now.
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I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
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