Question

this is a algebra pizzazz question what happened to the glass blower who inhaled?

Answer 1

hegotapaneinhisstomach

Answer 2

wondering the same thing....

Answer 3

Eat my gushy poo.

Answer 4

he got a pane in his stomach

Answer 5

hegotapaneinhisstomach

Answer 6

You'll find the answer when you correctly solve the problems.

Answer 7

Eat my gushy poo.

Answer 8

He got a pane in his stomach

Answer 9

He got a pane in his stomach

Answer 10

The correct answers are:

#1) Graph I;  #2) Graph O; #3) Graph C; #4) Graph E; #5) Graph N; #6) Graph G; #7) Graph M; #8) Graph H; #9) Graph T; #10) Graph S; #11) Graph P; #12) Graph A

He got a pane in his stomach.

Explanation:

#1) We want a graph where -4 is circled and not filled in, and -1 is circled and filled in; from -4, the graph goes to the right and from -1 it goes to the left, meeting between the two numbers and not extending further.  This is graph I.

#2) Solving the first inequality, we subtract 4 from each side; this gives us x > -1.  Solving the second inequality, we add 2 to each side; this gives us x < 4.  We want a graph where -1 is circled and not filled in, and 4 is circled and not filled in, with the line shaded between them.  This is graph O.

#3) We want a graph where -2 is circled and filled in and 3 is circled and not filled in; from -2, the graph is shaded left and from 3 the graph is shaded right.  This is graph C.

#4) Solving the first inequality, divide both sides by -3; this gives us t<-4 (remember we flip the symbol when we divide by a negative number).  Solving the second inequality, divide both sides by 5; this gives us t≥2.  We want a graph where -4 is circled and not filled in, and 2 is circled and filled in; from -4 the graph is shaded left and from 2 the graph is shaded right.  This is graph E.

#5) Solving the first inequality, subtract 5 from each side; this gives us 2n > -4.  Divide both sides by 2; this gives us n>-2.  Solving the second inequality, subtract 4 from each side; this gives us 3n>3.  Divide both sides by 3, and we have n>1.  This is and; this means we want an inequality showing n>-2 and n>1.  It has to be true for both numbers; this means we want a graph of n>1.  We want the number 1 circled and not filled in, and the graph shaded to the right; this is graph N.

#6) Solving the first inequality, subtract 9 from each side; this gives us -4u>-8.  Divide both sides by -4, giving us u<2.  Solving the second inequality, add 13 to each side; this gives us 7u≤7.  Divide both sides by 7; this gives us u≤1.  We want a graph showing that u<2 and u≤1; this means we want to go from the smaller number, so we want a graph of u≤1.  We want a graph where 1 is circled and filled in, and the line is shaded to the left; this is graph G.

#7) Solving the first inequality, subtract 20 from each side; this gives us 12≤3x, or 3x≥12.  Divide both sides by 3 and we have x≥4.  Solving the second inequality, subtract 1 from each side; this gives us 16>-8x, or -8x<16.  Divide both sides by -8, and we have x>-2.  We want a graph where 4 is circled and filled in and -2 is circled and not filled in; since this is "or" we include both answers.  This means everything from -2 to the right is shaded; this is graph M.

#8) Solving the first inequality, subtract 8 from each side; this gives us -2k<6.  Divide both sides by -2 and we have k>-3.  Solving the second inequality, subtract 1 from each side; this gives us 3k<0.  Divide both sides by 3 and we have k<0.  We want a graph where -3 is circled and not filled in and 0 is circled and not filled in; this is "or" so we include both possibilities.  Everything greater than -3 is shaded to the right and everything less than 0 is shaded to the left; this means everything is shaded, or graph H.

#9) Solving the first inequality, divide both sides by 5; this gives us w+4≥1.  Subtract 4 from each side and we have w≥-3.  Solving the second inequality, divide both sides by 2; this gives us w+4<6.  Subtract 4 from each side and we have w<2.  We want a graph where -3 is circled and filled in and 2 is circled and not filled in, with everything between them shaded; this is graph T.

#10) Solving the first inequality, divide both sides by 3; this gives us 6-y≤2.  Subtract 6 from both sides; this gives us -y≤-4.  Divide both sides by -1 and we have y≥4.  Solving the second inequality, subtract 6 from both sides; this gives us -y≥2.  Divide both sides by -1 and we have y≤-2.  There is no way to graph everything that is larger than a positive and less than a negative at the same time, so this is graph S, the empty set.

#11) Solving the first inequality, subtract 2x from each side; this gives us x<-3.  Solving the second inequality, subtract 4x from each side; this gives us 3x>-9.  Divide both sides by 3 and we have x>-3.  We want a graph where -3 is circled and not filled in, and everything on both sides is shaded; this is graph P.

#12) To solve first equation, multiply both sides by 2; this gives us x≤-4.  To solve the second equation, multiply both sides by -2; this gives us x≤0.  We want everything less than or equal to -4 or less than or equal to 0; this means we want everything smaller than 0, with 0 filled in.  This is graph A.