3 red balls, 4 green balls, and 5 yellow balls are in a bag
I got 47/66 that the balls are different colors...is that right?
Homework Answers
P(RR)=(3/12)(2/11)=6/132
P(GG)=(4/12)(3/11)=12/132
P(YY)=(5/12)(4/11)=20/132
Probability to draw two of same colour
=(6+12+20)/132=19/66
=>
Probability to draw two of different colours
=(66-19)/66=47/66
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