Question

There are 3 green marbles and 5 blue marbles in a bag and 4 red marbles....

  1. There are 3 green marbles and 5 blue marbles in a bag and 4 red marbles. Two marbles are drawn from the bag at random without replacement.
    1. Find the probability that both marbles are blue.
    2. Find the probability that the first is blue and the second green.
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Answer #1

There are total 12 marbles.

a)

P(both blue) = 5/12 * 4/11

= 0.1515

b)

P( first blue and second green) = 5/12 * 3/11

= 0.1136

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