Question

A compact disk, which has a diameter of 12.0 cm, speeds up uniformly from zero to 4.40 rev/s in 3.20 s What is the tangential acceleration of a point on the outer rim of the disk at the moment when its angular speed is 3.00 {rev/s}

A compact disk, which has a diameter of 12.0 cm, speeds up uniformly from zero to 4.40 rev/s in 3.20 s
What is the tangential acceleration of a point on the outer rim of the disk at the moment when its angular speed is 3.00 {rev/s}?
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Answer #1
tangential acc=radial acc*radius
radial acc=4.4*2PI/3.2
answered by: dee
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A compact disk, which has a diameter of 12.0 cm, speeds up uniformly from zero to 4.40 rev/s in 3.20 s What is the tangential acceleration of a point on the outer rim of the disk at the moment when its angular speed is 3.00 {rev/s}
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