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chameleons

Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable 280 for 20, then travels at constant speed for another 30.

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Answer #3

Its velocity at the end of 0.02 s is at = 210*0.02 = 4.2 m/s.

Distance traveled during this time is average velocity * time = 2.1*0.02 = 0.042m.

Distance traveled with this speed of 4.2m/s for another 0.03 s is 4.2*0.03 = 0.126m

The total distance = 0.042+0.126=0.168m

answered by: TC
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Answer #1
Its velocity at the end of 0.02 s is at = 280*0.02 = 5.6 m/s.

Distance traveled during this time is average velocity * time = 2.1*0.02 = 0.042m.

Distance traveled with this speed of 4.2m/s for another 0.03 s is 5.6*0.03 = 0.168m

total disstance = 0.042+0.168=0.21m
answered by: ske
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Answer #2

The first part is at constant acceleration starting from rest. d = (1/2)at^2. t is 0.02 seconds and a is given. Calculate that distance in meters.

The second part is at constant velocity, d = vt, with t = 0.03 seconds, and v is given. Calculate that distance in meters.

Add them up.

answered by: Griselda
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