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In the same mouse species, a third unlinked gene (gene C/c) also has an epistatic effect on fur...

In the same mouse species, a third unlinked gene (gene C/c) also has an epistatic effect on fur color. The presence of the dominant allele C (for color), allows theA/a and B/b genes to be expressed normally. The presence of two recessive alleles (cc), on the other hand, prevents any pigment from being formed, resulting in analbino (white) mouse.


Match the phenotypes on the labels at left to the genotypes listed below. Labels can be used once, more than once, or not at all.


agouti
solid color
solid color
agouti black
albino


AaBbcc
AaBBCC
Aabbcc

AAbbCc
aaBbCc
AABBcc
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Answer #1
AABBcc----------albino

Aa BB Cc-----agouti

brown-----aabbCc

black---------aaBBCc
answered by: Lucy King
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Answer #2
Because each gene segregates independently, you need to determine the probability of each genotype independently and then multiply the four probabilitiestogether. The probability of offspring with solid color (aa) is 1/4; the probability of offspring with black fur (BBor Bb) is 3/4; the probability ofcolored fur (CCor Cc) is 3/4; and the probability of piebald, or white patches (pp), is 1/4. The combined probability is1/4 x 3/4 x 3/4 x 1/4 = 9/256.
answered by: jas0n
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