A colorblind woman marries a man who is not colorblind. What is the phenotypic ratio of...
- A colorblind woman marries a man who is not colorblind. What is the phenotypic ratio of the offspring?
- In humans, freckles are dominant over absence of freckles, and curly hair is incompletely dominant with straight hair. A freckled, wavy-haired woman has kids with a freckled straight-haired man. Both the man and woman have one homozygous dominant parent and one homozygous recessive parent for freckles. What is the phenotypic ratio of the man and woman’s kids?
- Pigment in the mouse is only produced when the C allele is
present. Individuals of the cc genotype have no color (albino). If
color is present, it may be determined by the A or a alleles. AA or
Aa results in agouti (brown) color, while aa results in black
coats. In two crosses between agouti females whose genotypes were
unknown and males of the aacc genotype, the following phenotypic
ratios were obtained. What is the genotype of the agouti female in
each cross?
- 9 agouti, 10 black
-
- 4 agouti, 5 black, 10 albino
Homework Answers
1.
XcXc (colour blind woman) × XY (man with normal vision)
| Gametes | Xc |
| X | XcX normal female |
| Y | XcY colourblind male |
Phenotypic ratio = 1 : 1
2. Ff Cc (woman) × Ff cc (man)
| Gametes | Fc | fc |
| FC | FFCc freckles, wavy | FfCc freckles, wavy |
| Fc | FFcc freckles, straight | Ffcc freckles, straight |
| fC | FfCc freckles, wavy | ffCc no freckles, wavy |
| fc | Ffcc freckles, straight | ffcc np freckles, straight |
Phenotypic ratio = 3 : 3 : 1 : 1
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