Question

8. Dihybrid Genetics: In humans, Brown hair (R) is dominant while red hair (r) is recessive. Freckles (6) is dominant while no freckles (f) is recessive. % Harry Potter is homozygous dominant for freckles and heterozygous for red hair. What is his genotype? What is his phenotype? What gametes could he produce? Ginny Weasley is heterozygous for freckles and has red hair. What is her genotype? What is her phenotype? What gametes could she produce? What is the chance that their child will have red hair and freckles? (Hint: Do two Punnett Squares, one for each trait!)

Answer 1

question 7

part a)

X-linked recessive inheritance is a mode of inheritance in which a mutation in a gene on the X chromosome causes the phenotype to be always expressed in males (who are necessarily homozygous for the gene mutation because they have one X and one Y chromosome) and in females who are homozygous for the gene mutation.

rest are well explained in image.

PAGE NO.: DATE: answer No. b Given y Brown Hair (Dominant) as R Red Hair Crecesive) ar freckles (dominant) f No freckles Crecensiue) of Hurry potter Chomoyjous dominant a fou pre elles and Heteroufous for red hair) (fou freckles I ffor rr (red hair) Red hair comot be heteroujous as it is a recesive trait. at has to be Homozytowo receive to express med bair color. Genotype off Phenoty pe freckles and red hair. gametes that he can produce are for Peackles and red hair V ffrr oo gametes Ifr Ifr. lfr/ (fr -Ginny weasly Heterougeus teu freckles and has red hove Genotype + ffm y freckles with red hair. Gametes + ffor fr Ifr Phenotype

112 PAGE NO.: DATE: 1 Charents Harry and Ginny weasley for freckles - ff x f DJ Gameres ff] [f f F FF ff Freckles frukles EL freekies meckles tre All fowe will have freckles for red hair, r ar r red hair red hair red hair red had All four will have red hair. 9 would have been helemalyjous brown hair. R r Rr r m Half uus be with red Rr hain lil ( Browni red

PAGE NO.: DATE: ansuur noo] guer - Color Blindness is a recensiue sex linked (X-linked) disease. dominance law of b. Genotype of women who is not color blind let to recessive allele causing color blindness. x normal dominant allele Momen can be carreu or normal ✓ to C. For color blind a genety pe syt xe x* x+ Genotype + Xcgo de Carrier txt xe e Man who has color blindnes - - Xey f. Man who is normal txty Father's genotype Х 1x*x Parents Mother's gendly pe g gametes nix gly generation - xºx* xeya Female Feinale Carrior telor blindnes х*ү ху Male Male Normal Color blindnes

11 50% chances she will be color blind, a. Probability of color blind child + 2/4 + 1/2 b. Prob. of color blind cons 1/2 dany wer 1/2 d. A they have a son, there are 50% chances he will be color blind. daughter there are e. prob. of bi e if they have a

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