Question

BIO 142 Test X 9) Curly hair (CC) is incompletely dominant over straight hair (ce), therefore the heterozygous genotype (Ce) produces wavy hair (Ce), Set up the Punnet square and cross a mother with wavy hair with a man with wavy hair. (5 points) What is the percentage of different phenotypes of their children? Show your works. Female Genotype: Genotype ratio Phenotype ratio: Male Genotype: 10) Cross a father with blood type AO and a mother with BO blood type. (3 points) What is the percentage of different phenotypes of their children? Show your works. Female Genotype: Genotype ratio: Phenotype ratio: Male Genotype: 11) The abbreviation for hemoglobin is Hb. Let Hb Hb- sickle-cell anemia, Hb HbA- normal Hb (unaffected), and Hb Hb - sickle-cell trait Cross a mother with sickle-cell anemia and father with the sickle-cell trait. (5 points) notypes of their What is the percentage of different phe children? Show your works. Female Genotype: Genotype ratio Phenotype ratio: Male Genotype 12) Let XC dominant allele for normal vision and Xc-recessive allele for color blindness. Ind phenotype of the following alleles for recessive sex-linked color blindness.(3 points) XcY XcY

Answer 1

9)

Both mother and father have Cc genotypes.

On crossing we get

CC (curly) ; Cc (wavy) ; Cc (wavy) ; cc(straight)

Percentage of curly =25%

Wavy =50%

Straight =25%

12)

1-Normal

2-Color blind

3-Color blind

4-Normal