None of the resistors in the circuit shown in the drawing is connected in series or in parallel with one another. (Let I1 = 8.6 A, I2 = 6.2 A, and I3 = 12.2 A.)
(a) Find the current I5.this can be done by Kirchhoff's voltage rule
first applying it in left top square
moving anticlockwise
I1*4+I2*R2= 75
8.6*4+6.2*R2=75
R2=6.55 ohm
current in R4by Kirchhoff's current rule
I4=I1-I2
= 8.6-6.2
=2.4 A
now applying it in left lower loop
I4R4+I5R5=I2R2
2.4*2+2.2 I5 =6.2*6.55
I5=7.40 A
now applying it in right loop
I3R3+I5R5=75
12.2*R3+7.40*2.2=75
R3= 4.81 ohm
None of the resistors in the circuit shown in the drawing is connected in series or in parallel...
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