A 5.0 weightless strut, hinged to wall,
Homework Answers
From the figure cosθ = 3m/5mθ=53.13oAlso from the figure vertical component of force is Tsinθ= 800NThen T = (800N)/(sin53.13o)= 1000Nvertical component of force is T cosθ =(1000N)(cos53.13o)=600N
From the figure cosθ = 3m/5m
θ = 53.13o
Also from the figure vertical component of force is Tsinθ= 800N
Then T = (800N)/(sin53.13o)
= 1000N
vertical component of force is T cosθ =(1000N)(cos53.13o)
= 600N
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2.A picture P of weight W = 40 N is hung by two strings as
shown. The magnitude of the tension force
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