Question

half reaction anode

A certain electrochemical cell has for its cell reaction:

Zn + HgO ?ZnO + Hg

Which is the half-reaction occurring at the anode?

Question 4 options:

HgO + 2e– ? Hg + O2–


Zn2+ + 2e– ? Zn


Zn ? Zn2+ + 2e–


ZnO + 2e– ? Zn

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Answer #2

Given cell reaction is:

$$ \mathrm{Zn}+\mathrm{HgO} \longrightarrow \mathrm{ZnO}+\mathrm{Hg} $$

In the reaction, oxidation state of \(\mathrm{Zn}\) increases from 0 in \(\mathrm{Zn}\) to

\(+2\) in \(\mathrm{Zn} \mathrm{O}\), and the oxidation state of \(\mathrm{Hg}\) decreases from \(+2\) in \(\mathrm{Hg} \mathrm{O}\)

to 0 in \(\mathrm{Hg}\).

So, Zn undergoes oxidation and \(\mathrm{Hg} \mathrm{O}\) undergoes reduction. Thus the half reaction occuring at anode (oxidation) is:

$$ \mathrm{Zn} \longrightarrow \mathrm{Zn}^{2+}+2 \mathrm{e}^{-} $$

answered by: InterviewGod
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Answer #1

Zn => Zn2+ + 2e-

Oxidaton takes place at the anode.


answered by: Gotom
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