Given cell reaction is:
$$ \mathrm{Zn}+\mathrm{HgO} \longrightarrow \mathrm{ZnO}+\mathrm{Hg} $$
In the reaction, oxidation state of \(\mathrm{Zn}\) increases from 0 in \(\mathrm{Zn}\) to
\(+2\) in \(\mathrm{Zn} \mathrm{O}\), and the oxidation state of \(\mathrm{Hg}\) decreases from \(+2\) in \(\mathrm{Hg} \mathrm{O}\)
to 0 in \(\mathrm{Hg}\).
So, Zn undergoes oxidation and \(\mathrm{Hg} \mathrm{O}\) undergoes reduction. Thus the half reaction occuring at anode (oxidation) is:
$$ \mathrm{Zn} \longrightarrow \mathrm{Zn}^{2+}+2 \mathrm{e}^{-} $$
Zn => Zn2+ + 2e-
Oxidaton takes place at the anode.
A certain electrochemical cell has for its cell reaction: Zn + HgO rightarrow ZnO + Hg Which is the half-reaction occurring at the anode? a) HgO + 2e^- rightarrow Hg + O_2- b) Zn^2+ + 2e^- rightarrow Zn c) Zn rightarrow Zn^2+ + 2e^- d) ZnO + 2e^- rightarrow Zn
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