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Two capacitors C1 = 2 µF and C2 = 5 µF are initially charged to a potential difference of V =...

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Two capacitors C1 = 2 μF and C2 = 5 μF are initially charged to a potential difference of V = 100 V. They are inserted into the circuit with opposite polarities asshown. Switches S1 and S2 are now closed. What is the magnitude of the potential difference between points A and B? (Answer in Volts.)

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Answer #1

Initial charge on C1 = 100 * 2 =200
Initial charge on C2 = 100*5 =500

When switches are closed
charge on each capacitor Q= Q1 + Q2 =200 + 500 = 700

Total charge = 1400

C effective = C1+C2 =2+5 =7 (parallel)

Voltage across AB = Q/C= 200V

answered by: Anony Mous
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