freezing point depreesion
Homework Answers
Step1 Let M be molar mass of solute ; Moles of solute =1.2463/M
Step2 ΔTf= 4.9 ; Kf= 9.8 C/m
Step3 Molality of solute =(1.2463/M)(1000/10.9303)
Step4 ΔTf = Kf xMolality ; 9.8x1.2463x1000/Mx 10.9303 =4.9
Step5 M= 228.04
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please help ! 26. The freezing point depression of a solution of 1.45g sample of an...
please help !
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please help !
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