Question

A hockey goalie is standing on ice. Another player fires a puck (m = 0.17 kg) at the goalie with a velocity of +62 m/s. Instead of catching the puck, the goalie slapsit with his stick and returns the puck straight back to the player with a velocity of -65 m/s. The puck and the stick are in contact for a time of 4.30 10-3 s. Nowwhat is the average force exerted on the goalie by the puck?

Answer 1

given mass m = 0.17 kg , v1 = 62 m/s , v2 = -65 m/s , time t = 4.3*10^-3 sec

from impulse - momentum theorem

F *t =m(v2-v1)

solving we get

F = 5020 N