Question

chemical equilibrium

2.50 mol NOCl was placed in a 2.50 L reaction vessel at 400ºC.After equilibrium was established, it was found that 28% of theNOCl had dissociated according to theequation 2NOCl(g) Picture2NO(g) +Cl2(g).

Calculate the equilibrium constant, Kc, for thereaction.
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Answer #1
The concentration of NOCl = Number of moles /volume of solution=2.5 mol/2.5 L=1.0 MAt equilibrium 28 % of NOCl is dissociated∴ The concentration of NOCl at equilibrium =(1.0-0.28)M=0.72MThe concentration of NO atequilibrium = 0.28 MThe concentration of Cl2atequilibrium = 0.14 MKc =[NO]2[Cl2]/[NOCl]2=(0.28M)2*(0.14M)/(0.72M)2=2.117*10-2
answered by: babewithbrains
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