A gun has a muzzle speed of 90 meters per second. What angle of elevation should be used to hit...
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A gun has a muzzle speed of 90 meters per second. What angle of elevation should be used to hit...
If a projectile is fired with an initial velocity of vo meters per second at an...
If a projectile is fired with an initial velocity of vo meters per second at an angle a above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations x = (vo cos(a)t y = (vo sin(a)t - +- 1012 where g is the acceleration due to gravity (9.8 m/s2). (Round your answers to the nearest whole number.) (a) If a gun is fired with a = 30°...
1. If a projectile is fired with an initial velocity of vo meters per second at...
If a projectile is fired with an initial velocity of v0 meters per second at an angle α above the horizontal, and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equationsx=(v0 cos α) t y=(v0 sin α) t-1/2 g t2where g is the acceleration due to gravity (9.8 m / s2)(a) If a projectile is fired with α=45° and v0=900 m / s, when will it hit the ground? How...
a bullet is fired from a rifle with a muzzle velocity of 80 meters per second...
a bullet is fired from a rifle with a muzzle velocity of 80 meters per second at an angle of 30 degrees from the horizontal. How far away does the bullet hit the ground? How long does it take the bullet to hit the ground? What is the maximum height of the bullet's path?
Problem 1. You aim a BB gun at a monkey hanging from a "tree." At the...
Problem 1. You aim a BB gun at a monkey hanging from a "tree." At the instant the BB is fired, the monkey drops from the tree. First, we estimate that the initial angle of the BB gun is 30° above horizontal and aimed directly at the monkey, and the tree the monkey falls from stands 5 m away. The BB has an initial speed of about 10 m/s, we'll neglect air resistance and use that he acceleration İom gravity...
You are trying to hit a target that is horizontally 3.5 meters away and 1.8 meters...
You are trying to hit a target that is horizontally 3.5 meters away and 1.8 meters higher than the projectile launcher. The launcher nuzzle is fixed at a 46 degree angle with respect to the horizontal line. Find the velocity in meters per second that will result in a hit. g = 9.8 m/s2.
A ball is thrown with a speed of 20 m/s at an angle of 37# above...
A ball is thrown with a speed of 20 m/s at an angle of 37# above the horizontal (neglect air resistance). Which of the following is true: A. at the highest point its acceleration is zero. B. the velocity of the object is zero at the point of maximal elevation. C. the velocity in the horizontal direction is constant. D. the acceleration depends on the mass of the object.
Q. No 4: Your hit a football within initial speed of 25.0 m/s as it the...
Q. No 4: Your hit a football within initial speed of 25.0 m/s as it the ball exhibits projectile motion. The football player adjusts the angle of elevation a of the ball until the ball takes 3.00 s to reach the goalkeeper at another end that is 45.0 m away. Ignore air resistance. (a) Find the angle at which the footballer hit the ball. (b) Find the speed and acceleration of the ball at the highest point in its trajectory....
If an object is thrown with a velocity of v feet per second at an angle...
If an object is thrown with a velocity of v feet per second at an angle of θ with the horizontal, then its flight can be modeled by, x = (v cos θ ) t and y = v (sin θ ) t - 16 t2 + h where t is in seconds and h is the object's initial height in feet above the ground. x is the horizontal position and y is the vertical position, and - 16 t2...
A The Earth exerts a gravitational pull of 2.0 ×1020 N on the Moon; the Sun...
A The Earth exerts a gravitational pull of 2.0 ×1020 N on the Moon; the Sun exerts a gravitational pull of 4.3 ×1020 N on the Moon.What is the net force on the Moon when the angular separation between the Earth and the Sun is 90 as seen from the Moon? B : A gun on the shore (at sea level) fires a shot at a ship which is heading directly toward the gun at a speed of 40 km/h....
e4) The acceleration due to gravity on the earth's surface is a =-980665k meters per second...
e4) The acceleration due to gravity on the earth's surface is a =-980665k meters per second squared. For this problem, let's approximate this as a =-10k m/(sec2). This means that gravity acting on a 5 kg object exerts a force of F ma 50k N, where N, a Newton, is a unit of force equal to a kg·m/ (see) If I raise a 5 kg object up 7 meters, I must do 350 J of work, where J, a Joule,...
If a projectile is fired with an initial velocity of vo meters per second at an angle a above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations x = (vo cos(a)t y = (vo sin(a)t - +- 1012 where g is the acceleration due to gravity (9.8 m/s2). (Round your answers to the nearest whole number.) (a) If a gun is fired with a = 30°...
Problem 1. You aim a BB gun at a monkey hanging from a "tree." At the instant the BB is fired, the monkey drops from the tree. First, we estimate that the initial angle of the BB gun is 30° above horizontal and aimed directly at the monkey, and the tree the monkey falls from stands 5 m away. The BB has an initial speed of about 10 m/s, we'll neglect air resistance and use that he acceleration İom gravity...
Q. No 4: Your hit a football within initial speed of 25.0 m/s as it the ball exhibits projectile motion. The football player adjusts the angle of elevation a of the ball until the ball takes 3.00 s to reach the goalkeeper at another end that is 45.0 m away. Ignore air resistance. (a) Find the angle at which the footballer hit the ball. (b) Find the speed and acceleration of the ball at the highest point in its trajectory....
e4) The acceleration due to gravity on the earth's surface is a =-980665k meters per second squared. For this problem, let's approximate this as a =-10k m/(sec2). This means that gravity acting on a 5 kg object exerts a force of F ma 50k N, where N, a Newton, is a unit of force equal to a kg·m/ (see) If I raise a 5 kg object up 7 meters, I must do 350 J of work, where J, a Joule,...
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