the perimeter of a standard basketball court is 288 ft

Question

Question

the perimeter of a standard basketball court is 288 ft. find the dimensions of the basketball court if its length is 44ft. longer than its width.

Answer 1

Answer #1

width=x=50ft length=x+44=94ft ----------- p=2w+2L 2x+2(x+44)=288 2x+2x+88=288 4x=200 x=50

answered by: NY-Calc

Answer 2

Answer #2

2X+2(X+44)=288 2X+2X+88=288 4X=288-88 4X=200 X=200/4 X=50 FT. IS THE WIDTH. 50+44=94 FT. IS THE LENGTH. PROOF: 2*50+2*94=288 100+188=288 288=288

answered by: student3

Answer 3

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