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a scuba diver shine a flashlight from beneath the surface of water (n=1.33) such that the light...

a scuba diver shines a flashlight from beneath the surface of water (n=1.33) such that the light strikes the water-air boundary with an angle of incidence of 43.at what angle is the beam refracted?

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Answer #1

n1sinθ1 = n2sinθ2

1.33sin43 = 1sinθ2

sinθ2 = 0.9071

θ2 = 65.102


answered by: GHOST
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