a scuba diver shines a flashlight from beneath the surface of water (n=1.33) such that the light strikes the water-air boundary with an angle of incidence of 43.at what angle is the beam refracted?
n1sinθ1 = n2sinθ2
1.33sin43 = 1sinθ2
sinθ2 = 0.9071
θ2 = 65.102
a scuba diver shine a flashlight from beneath the surface of water (n=1.33) such that the light...
A diver shines a flashlight upward from beneath the water at a 42.5? angle to the vertical. The index of refraction of water is 1.33. (a.) Determine the angle at which light is reflected at the water-air surface. (b.) Calculate the angle at which the light leaves the water.
Constants v Part A A diver shines a flashlight upward from berieath the water (n- 1.33) at a 38.7 angle to the vertical At what angle does the light leave the water? Express your answer using three significant figures. 82 Submit Request Answ Provide Feedback
A beam of light strikes the surface of water at an incidence angle of 60°. Determine the directions of the reflected and refracted rays. For water, n=1.33. A- (a) 30° reflected into air, (b) 22° refracted into water B- (a) 60° reflected into air, (b) 41° refracted into water C- (a) 90° reflected into air, (b) 60° refracted into water D- (a) 41° reflected into air, (b) 30° refracted into water
Light in the air (n1= 1) strikes the surface of a lake (n2= 1.33 for water), making an angle of 37orelative to vertical. The RMS value of the magnetic field in the incident light is 1.65x10-7T. a) What is the angle (relative to vertical) of the reflected beam? b) What is the angle (relative to vertical) of the refracted beam? c) What is the average intensity of the incident light?
answer questions 11-13 SOLVE FOR 12
QUESTION 11 Challenge Question: A scuba diver is a flashlight pointing upwards at the surface of the sea. If the incident beam makes an angle of 23 degrees with the normal to the water's surface, then what is a possible angle of the refracted beam in the alr? (Hint: Like Sherlock Holmes, Eliminate the Impossible, what remains must be the truth (Hint: Consider total internal reflection) O a. 170 Ob. 230 OC 360 d....
Light that is traveling through water (index of refraction is
n=1.33) strikes a glass surface (index of refraction n=1.50) at an
incident angle of θi=48.1°.
What is the the angle of refraction, θr, of the light in
the glass?
Light that is traveling through glass (index of refraction is
n=1.50) strikes an air surface (index of refraction n=1.00) at an
incident angle of θi=27.9°.
What is the the angle of refraction, θr, of the light
in the air?
Water Glass
1.33 1. Light travels from glass to water. It strikes the boundary at an angle of 45 degrees. At what angle is the refracted ray in the water? Tour dot snell's Law = n, sing, = n₂sina O a= na sinde Az = 1 o sin45 - 12 The mount Port nge. The e an
Can
you answer both questions with clear writing please
4. Light from the sun strikes the flat surface of a lake at an angle of 35.0° relative to the lake's surface normal. A scuba diver deep in the lake's water wants to look at the sun. At what angle must the diver look to see the sun, relative to the lake's surface normal? 5. A beam of light travels from air into glass. Its angle of incidence is 45° and...
Can
u answer both questions with clear writing please
4. Light from the sun strikes the flat surface of a lake at an angle of 35.0° relative to the lake's surface normal. A scuba diver deep in the lake's water wants to look at the sun. At what angle must the diver look to see the sun, relative to the lake's surface normal? 5. A beam of light travels from air into glass. Its angle of incidence is 45° and...
A ray of light strikes the surface of water (n = 1.33) at an angle of 60.0° from the water surface. What is the angle of refraction? ***Don’t forget to measure angle from the normal*** Question 9 options: a) 30.0° b) zero c) 22.1° d) 60.0°