There are no minimized variables in the given question because in every state the output is varying
and also no state is matching with other states..
If the state and the corresponding output is matched then only we can replace that state by another state. In the given problem
that is not possible so no minimization .so the states are not reducible.
3. Minimize the number of states for the state table below. Provide a reduced state table Next St...
3. Use the partitioning method from Chapter 6 to find a reduced state table. Assume each possible value for the don't care entries. Which values yield the minimum number of states? For each value, you must show the final state partition. For the value with the fewest number of states, provide the reduced state table. Next State Present State 00 01 10 11 Output S0 80 81 S1 S2 S1 S2 S2 S3 S2 S3 S3 S4 0 S2 S3...
Consider the following state diagram, which items on the state table is correct for the switch between states and output values. (Fig. 31) So S1 YO S Sz %0 Ss S2 S4 0 So Next state Z2Z1 Current state A. B. C. D. S4 S5 S6 S7 X=0 54 S5 S5 S5 X=1 X=0 S1 01 S6 00 S7 01 S4 10 Fig. 31 X=1 10 00 00 00 A. Line A on the table OB Line B on the...
Consider the following state diagram, which items on the state table is correct for the switch between states and output values. (Fig. 30) So S7 Food S Sz SS l%0 S2 Sc 70 %0 So Next state Z2Z1 Current state A. B. C. D. SO S1 S2 S3 X=0 S3 S4 S3 S3 X=1 X=0 S1 00 S1 01 10 S4 00 Fig. 30 X=1 00 00 10 00 S2 A. Line A on the table Line B on the...
A sequential circuit has one input (X), a clock input (CLK), and two outputs (S and V). X, S and V are all one-bit signals. X represents a 4-bit binary number N, which is input least significant bit first. S represents a 4-bit binary number equal to N + 3, which is output least significant bit first. At the time the fourth input occurs, V = 1 if N + 3 is too large to be represented by 4 bits;...
(10%) Draw the State Table using the above table. Is this a Mealy or Moore Model design? (15%) Design a Sequential FSM machine for it, using at least 1 JK type flip flop. (5%) Draw the Circuit diagram. Consider the following state diagram, where states are so = 00, S1 = 01, S2 = 10 , S3 =11 1/1 Reset 1/0 1/0 0/0 C S3 1/01 0/0
a) A synchronous finite state machine (FSM) is described by the state table in Fig. 3. Show how redundant states may be found and eliminated to minimise this FSM. [15 marks) b) Derive Boolean equations for the implementation of the reduced FSM. (15 marks] Next state Output Current X1Xo state 00 01 11 10 Z1Zo A A F E C 00 B C B A 01 F A B C 00 G DİACİ 10 Figure 3 Tum over... a) A...
5) Decoders: Given the following circuit, S0 and S1 are computed using a 4-2 priority encoder with the priorities indicated on the figure. (hint: IDLE signal is always 0, if any of the inputs 10,11,12, or 13 is 1) 6 points) 4-to-2 Priority Encoder 10 YO YI 13 IDLE 13> 11 > 12>10 12 Full c Adder So Fill the following table showing the output signals S0 and SI given the input signals w, x, y, a) and z. Prof...
Please show how you did this in excel. :13-19 Every home football game for the past eight years at Eastern State University has been sold out. The revenues from ticket sales are significant, but the sale of food, beverages, and souvenirs has contrib- uted greatly to the overall profitability of the football program. One particular souvenir is the football pro- gram for each game. The number of programs sold at each game is described by the following probabil- ity distribution:...
Its logic design my sequence is 127605 i need help with all this pages please and thank you 27 60 Experiment 4 Six-State Up-Down Counter 1 Objective To become familiar with the design procedures of a counter, which are applicable to the design of other synchronous sequential circuits. 2 Problem description A six-state up-down counter is to be designed. Three flip-flops with outputs Q2,Qi and Qo are required in the design. As shown in Figure 1, the counter is initialized...
Complete the profile leveling field notes below, then answer questions 78-86 that follow. STATION HL ROD ELEVATION BM-1 100.00 0100 1.40 0+50 1400 2.60 3.60 4.90 1+50 TP-1 2400 12.39 5.20 2+50 3+00 7.90 8.60 3+50 | TP-2 . 10.66 8.80 12.70 5+00 BM-2 9.36 78. What is the elevation of the very first H.L.? A. 95.32 B 4.68 c. 1.48 D. 104.68 None of the above 79. B What is the elevation of Station 0+00? A 1.40 101.40 10/6.08...