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4) large oil company produces two grades of gasoline: regular and super-unleaded. To produce these gasolines, equipment is us
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Answer #1

The given question involve input-output model:

The model involves following equations

X1= a11X1+a12X2+c1-------eq(1)

X2= a21X1+a22X2+c2-------eq(2)

Where X1 is the value of the total production of good 1, X2 is the value of the total production of good 2;

c1 is the value of the final consumption of good 1, c2 is the value of the final consumption of good 2;

a11 is worth good 1 required to produce good 1, a12 is worth good 2 required to produce good 1;

a21 is worth good 1 required to produce good 2, a22 is worth good 2 required to produce good 2;

Solving eq(1)and (2) we will get the following value of X1 and X2

\tiny X_{1}=\frac{(1-a_{22})c_{1}+a_{12}c_{2}}{(1-a_{11})(1-a_{22})-a_{12}a_{21}}-------------eq3

\tiny X_{2}=\frac{(1-a_{11})c_{2}+a_{21}c_{1}}{(1-a_{11})(1-a_{22})-a_{12}a_{21}}--------------eq4

Now, for this question

a11= $0.14, a21= $0.15, c1= $10 million ( assume each regular cost $1 )

a12= $0.17,  a22= $0.11, c2= $15 million ( assume each super-unleaded cost $1 )

Put all value into eq3 and eq4 to find out X1 and X2

X1= 15.47

X2= 19.46

If final consumption c1 increases by $1million and c2 increases by $2million. Then new c1 would be $11million and c2 would be $17million.

Corresponding new outputs in two sectors, after solving with eq3 and eq4, would be

X1= 17.13

X2= 21.98

Good luck!!

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