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I wish to have a computer whose machine-level instructions are all 32 bits each. If I want to have all instructions of the fo

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Answer #1
number of instructions = 500
number of bits = log(500) = 9

remaining number of bits = 32 - 9 = 23

number of registers in instruction = 3
number of bits per register = 23/3 = 7

number of registers = 2^7 = 128

Answer: E.  128
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