Emergency Condition | ||||
Display Panel | 1 | 2 | 3 | 4 |
A | 18 | 26 | 33 | 14 |
18 | 26 | 36 | 14 | |
B | 15 | 22 | 30 | 12 |
11 | 18 | 31 | 5 | |
C | 22 | 28 | 35 | 10 |
23 | 32 | 38 | 15 | |
Two-way ANOVA: Time versus Panel, Condition | |||||
Source | DF | SS | MS | F | P |
Panel | 2 | 144.542 | 144.542 | 25.32 | .0000 |
Condition | 3 | 1,647.12 | 549.042 | 96.18 | .0000 |
Interaction | 6 | 24.25 | 4.042 | .71 | .6498 |
Error | 12 | 68.50 | 5.708 | ||
Total | 23 | 2,028.96 | |||
Tabulated statistics: Panel, Condition | |||||
Rows: | Panel | Columns: | Condition | ||
1 | 2 | 3 | 4 | All | |
A | 15.00 | 26.00 | 34.50 | 13.00 | 22.13 |
B | 13.00 | 20.00 | 30.50 | 7.50 | 17.75 |
C | 22.50 | 30.00 | 36.50 | 16.00 | 26.25 |
All | 17.67 | 25.33 | 33.83 | 12.17 | 22.04 |
(e) Make pairwise comparisons of emergency conditions 1, 2, 3, and 4 by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
u1 – u2: | [ , ] | |
u1 – u3: | [ , ] | |
u1 – u4: | [ , ] | |
u2 – u3: | [ , ] | |
u2 – u4: | [ , ] | |
u3 – u4: | [ , ] | |
(f) Which display panel minimizes the time required to stabilize an emergency condition? Does your answer depend on the emergency condition? Why?
(Click to select)Panel APanel BPanel C minimizes the time required
to stabilize an emergency condition. (Click to select)YesNo, there is (Click to select)someno interaction. |
(g) Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places.)
Confidence interval [ , ]
Answer:
MINITAB used.
The ANOVA results are different for this given data.
Analysis of Variance
Source |
DF |
Adj SS |
Adj MS |
F-Value |
P-Value |
Panel |
2 |
228.58 |
114.292 |
19.32 |
0.000 |
condition |
3 |
1651.00 |
550.333 |
93.01 |
0.000 |
Panel*condition |
6 |
32.75 |
5.458 |
0.92 |
0.512 |
Error |
12 |
71.00 |
5.917 |
||
Total |
23 |
1983.33 |
(e) Make pairwise comparisons of emergency conditions 1, 2, 3, and 4 by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Tukey Simultaneous Tests for Differences of Means
Difference |
Difference |
SE of |
Simultaneous |
T-Value |
Adjusted |
2 - 1 |
7.50 |
1.40 |
(3.33, 11.67) |
5.34 |
0.001 |
3 - 1 |
16.00 |
1.40 |
(11.83, 20.17) |
11.39 |
0.000 |
4 - 1 |
-6.17 |
1.40 |
(-10.34, -2.00) |
-4.39 |
0.004 |
3 - 2 |
8.50 |
1.40 |
(4.33, 12.67) |
6.05 |
0.000 |
4 - 2 |
-13.67 |
1.40 |
(-17.84, -9.50) |
-9.73 |
0.000 |
4 - 3 |
-22.17 |
1.40 |
(-26.34, -18.00) |
-15.78 |
0.000 |
Individual confidence level = 98.83%
u1 – u2: |
[-11.67 ,-3.33 ] |
|
u1 – u3: |
[-20.17,-11.83 ] |
|
u1 – u4: |
[2.00 , 10.34 ] |
|
u2 – u3: |
[ -12.67, -4.33 ] |
|
u2 – u4: |
[9.50 ,17.84 ] |
|
u3 – u4: |
[ 18.00, 26.34 ] |
|
(f) Which display panel minimizes the time required to stabilize an emergency condition? Does your answer depend on the emergency condition? Why?
(Click to select)Panel BPanel minimizes the time
required to stabilize an emergency condition. |
(g) Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places.)
Confidence interval [ -7.19, 24.19 ]
Mean=8.5 and se= 7.2
T table value at 0.05 level=2.179
Lower limit= 8.5-2.179*7.2 = -7.1888
upper limit= 8.5+2.179*7.2 = 24.1888
Means
Term |
Fitted |
SE Mean |
Panel |
||
A |
23.125 |
0.860 |
B |
18.000 |
0.860 |
C |
25.375 |
0.860 |
condition |
||
1 |
17.833 |
0.993 |
2 |
25.333 |
0.993 |
3 |
33.833 |
0.993 |
4 |
11.667 |
0.993 |
Panel*condition |
||
A 1 |
18.00 |
1.72 |
A 2 |
26.00 |
1.72 |
A 3 |
34.50 |
1.72 |
A 4 |
14.00 |
1.72 |
B 1 |
13.00 |
1.72 |
B 2 |
20.00 |
1.72 |
B 3 |
30.50 |
1.72 |
B 4 |
8.50 |
1.72 |
C 1 |
22.50 |
1.72 |
C 2 |
30.00 |
1.72 |
C 3 |
36.50 |
1.72 |
C 4 |
12.50 |
1.72 |
Emergency Condition Display Panel 1 2 3 4 A 18 26 33 14 18 26 36 14 B 15 22 30 12 11 ...
Ages Number of students 15-18 19-22 23-26 27-30 31-34 35-38 2 4. 9 6i 3 Based on the frequency distribution above, is 4 a: OUpper class limit Class boundary Lower class limit Class midpoint Class width
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