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Question 1: ​When creating the calibration curve during week 1, it was determined that [KSCN] = [...

Question 1: ​When creating the calibration curve during week 1, it was determined that [KSCN] = [FeSCN​2+​] at equilibrium. Explain why these two concentrations were equal in terms of the relative concentrations of each reactant, the limiting reactant, and the direction in which the reaction proceeded

Question 2: ​Describe the process by which equilibrium concentrations of the reactants and product were determined. Include in your discussion, how the equilibrium (final) concentration of FeSCN​2+​ was determined using a calibration curve, mole-to-mole ratios and how an ICE table should be completed. Explain which values were subtracted and added, and why

Question 3: ​What was the experimentally determined K​eq​ average? What is the theoretical K​eq​ for this reaction? How does your experimental value compare to the theoretical value and what are some factors that may have played a role in causing differing values

Question 5: ​Based on your experimentally determined K​eq​ value, are products or reactants favored? Explain your reasoning in terms of what it means to have a relatively small K​eq​ versus a relatively large K​eq​?

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Answer #1

1. The equilibrium reaction is given as

Fe3+ (aq) + SCN- (aq) ---------> FeSCN2+ (aq)

The equilibrium constant is given as

Kc = [FeSCN2+]/[Fe3+][SCN-]

The concentration of Fe3+ is so chosen that [Fe3+] >> [SCN-]. In order to keep Kc constant, [FeSCN2+] must increase to neutralize the effect of increased [Fe3+].

As per the stoichiometric equation, Fe3+ and SCN- react on a 1:1 molar ratio. Again,

1 mole Fe3+ = 1 mole SCN- = 1 mole FeSCN2+.

Since [Fe3+] >> [SCN-], hence, the amount of FeSCN2+ formed in moles/L is equal to the molar concentration of SCN-. The equilibrium reaction essentially proceeds in the forward direction giving more FeSCN2+.

2. In the first part of the experiment, the calibration curve is plotted by reacting excess Fe3+ with SCN- to give FeSCN2+. A series of standard FeSCN2+ solutions are prepared by taking a large excess of Fe3+ and varying amounts of SCN-. The absorbances of the standard solutions are measured and plotted against the known concentrations of SCN- (which is equal to [FeSCN2+]) to produce a calibration curve with regression equation y = mx + c where m is the slope of the plot.

In the second part of the experiment, the absorbances of the unknown FeSCN2+ solutions are measured and fitted in the regression equation to get the concentration of unknown FeSCN2+.

Let us start with known concentrations x of Fe3+ and SCN- and let the equilibrium concentration of FeSCN2+ be calculated as y. Therefore, the ICE chart is set up as

Fe3+ (aq) + SCN- (aq) ---------> FeSCN2+ (aq)

initial                                 x                x

change                              -y               -y                                   +y

equilibrium                   (x – y)         (x – y)                                y

The value of the [FeSCN2+] was subtracted from the initial concentrations of Fe3+ and SCN- because only a small portion of the reactants reacted to produce FeSCN2+ and the major portion was left as excess.

3 + 4. Need experimental data.

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