Question

2. (7 points) The following reactants were supplied to a cell-free extract that included a transaldolase and all of the enzymes of glycolysis. If the sedoheptulose-7-phosphate was labeled as seen below, show the products of the transaldolase reaction and indicate which product would enter glycolysis (hint: only one of the products of the transaldolase reaction enters glycolysis). Make sure the labeled carbon is clearly Indicated. Where would the labeled carbon end up in pyruvate (use a structure of pyruvate to show this)? Partial credit will be given but only if you show your work (you don't need all of the intermediates of glycolysis to show this) CHOH

Answer 1

Np eidae eacttou (Phase) Cu2bH Stepd- CHo C HoH HoH CHO C Ho CHOH CHol 2 五uuctese 6-phesphat 4 Phophals gedokeptulose 1-Phosphate CH oH CHo C Hou C Hot C나014 Buctose Fruutose-6-Phosphate 37 2 2- C D ildlo l CpH phophala ase CHOH cub oPog Frucbose

CHo of o3 Cop au e step 5 0 ATP COPO 2 0% CH2 erruwak

The carbon labelled intermediate reactions are shown above!

Description:

1).The glyceraldehyde 3 Phosphate and sedoheptulose 7 phosphate (Carbon labelled) reacts with help of enzyme transaldolase to from fructose 6 phosphate (Carbon labelled) and erythose 4 phosphate.This is non oxidative phase, where the reaction takes place at pentose phosphate pathway.

2).From Step 2 to Step 6 are the intermediate process. Where carbon labelled fructose 6 phosphate enter into glycolysis pathway (oxidative phase) and results in formation of pyruvate.