Question

7. What is the pH of a 0.22 M solution of cyclohexylammonium chloride salt solution? (KHcyclohexylammonium 3.69 x 104)

Answer 1

given salt cyclohexylammonium chloride CGH1NH3C Initial concentration of CsHuNH3CI Dissociation constant of C6HN3C = 0.22 M 0.22 mol,L-1 -KH-3.69x10-4-0.000369 Construct ICA table to obtain their equilibrium concentrations: Initial (M)0.2:2 0 0 Change (M) Equilibrium(M) 0.22-x Equilibrium expression: [ H3O [CGH11NH2 ] [ C6H11NH3CI ] Dissociation constant KH - x | [x 1 3.69x104- 0.22-х [ x 1 [x 1 [ 0.22-x ] 0.000369 - calculating x Vair0,08- o x" + 0.000369 x - 0.00008 118 =0 The equilibriumconcentration of C6H11NHsCl The equilibrium concentration of H* The equilibrium concentration of C6HuNH2 X By solving the above quadratic equation, we getx0.008827 M 0.22-x= 0.2112 M - X 0.008827 M x0.008827 M Calculating pH: with [H+] = 0.008827 M pH =-log [H+] pH -log [ 0.008827 1 pH2.05