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Question 9 (6 pts) How does a decrease in temperature affect the partial pressure of the underlin...

Question 9 (6 pts)
How does a decrease in temperature affect the partial pressure of the underlined substance and the
value for Keq for each of the following reactions? Explain your answer!
a) C(graphite) + 2H2(g)  CH4(g) ∆H0 = -75 kJ
b) N2(g) + O2(g)  2NO(g) ∆H0 = 181 kJ
c) P4(s) + 10Cl2(g)  4PCl5(g) ∆H0 = -1528 kJ

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Answer #1

Soluhian 24(1), dtt-p-75KT a、 C(graphite) +2H2(g) ic 、H2 goes downand CHI goes up ,decvea)ing lemperatun (b) Reoction is endothesimic, So a decvea in Jempralune. Shit tha equilrbrium to the eft hnd Side of thcl goes down and Pel goesup. un. with decreain empraluo

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