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Consider the phase change of cesium: Cs(l) → Cs(g) Calculate the temperature (in ºC) at which the...

Consider the phase change of cesium:

Cs(l) → Cs(g)

Calculate the temperature (in ºC) at which the vaporization of cesium occurs at 1 atm assuming ΔH and ΔS are nearly temperature independent.

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Answer #1

We know,

\DeltaHVap. = 63.9 KJ/Mol

= 63900 J/Mol

\DeltaSVap. = 67.69 J/Mol.K

Let us consider,

\DeltaSVap. = ( \DeltaHVap. / Tb ) Where Tb is boiling temperature

Tb= \DeltaHVap /  \DeltaSVap.

= (63900 / 67.69)

= 944 K ( convert Kelvin into degree C )

= 944 - 273

Tb = 671 0 C

Therefore, the temperature = 6710 C

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