Question

Calculate the volume change (in Liters) during the combustion of propane in which ΔE = -3083.67...

Calculate the volume change (in Liters) during the combustion of propane in which ΔE = -3083.67 kJ and ΔH = -3087.12 kJ at a constant pressure of exactly one atm and constant temperature.

C3H8(g) + 5 O2(g) ↔ 3 CO2(g) + 4 H2O(l)


The product of pressure and volume change should give units of L*atm. It can be shown that 1 L*atm = 101 J.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

By first law of the mo alynamics DE= qtw - DE 9-POW At constant pressure q = Dn. Thus, IDE= Ah-PAV, Given, DE2 - 3083.67 kJ =If you have any query regarding this you may ask in comments

Add a comment
Know the answer?
Add Answer to:
Calculate the volume change (in Liters) during the combustion of propane in which ΔE = -3083.67...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT