Homework Answers
The half life of fluorine-18 is missing in the question.
A value of 109.77 minute for half life of Fluorine-18 is found from the internet. Kindly use the value in the reference provided along with the question.
Total time from 7 am to 4.10 pm in minutes will be 550 minutes.
No of half lives = 550 min/ 109.77 min
= 5.01
The amount remaining = (0.5)no of half lives x Initial amount
= (0.5)5.01 x 160 mg
= 5 mg
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