Question

Classify the following monosaccharides according to the position of the carbonyl group and the number of carbon atoms in the molecule.

Answer 1

General guidance

Concepts and reason

The concept used to solve this problem is to classify the given compounds based on the position of the carbonyl group and the number of carbon atoms present in each compound.

All the given compounds are monosaccharides.

Fundamentals

Monosaccharides are classified as aldose and ketose. The term, \u2018Aldo\u2019 indicates the presence of aldehyde and \u2018keto\u2019 represents ketone.

Aldopentoses are five-carbon sugars with three chiral centers. Aldotetroses are four-carbon sugars with two chiral centers. Aldohexoses are six-carbon sugars with four chiral centers.

Step-by-step

Step 1 of 3

The structure is as follows:

This is a ketotetrose.

The given compound is classified as follows:

Explanation

The compound contains four carbon atoms in the long chain. Here, the keto group is present at the 2^nd carbon atom.

So, the compound is classified as ketotetrose.

Step 2 of 3

The structure is as follows:

This is a ketohexose.

The given compound is classified as follows:

Explanation

The compound contains six carbon atoms. Here, the keto group is present at the 2^nd carbon atom.

So, the compound is classified as ketohexose.

Step 3 of 3

The structure is as follows:

Glucose is an aldohexose.

The given compound is classified as follows:

Explanation

The compound, glucose contains six carbon atoms. Here, the aldehyde group is present at the 1^st carbon atom.

So, the compound is classified as aldohexose.

Answer

The given compound is classified as follows:

The given compound is classified as follows:

The given compound is classified as follows:

Answer only

The given compound is classified as follows:

The given compound is classified as follows:

The given compound is classified as follows: