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Problem 112: treat the peaks at 2.3 ppm as two singlets, as the 1BC NMR confirms.
Problem 112 IR Spectrum 4000 3000 2000 1600 1200 V (cm) Mass Spectrum uv Spectrum 100 A,s. 265 nm (log10ε 2.6) λ max 271 nm 0
Problem 112: treat the peaks at 2.3 ppm as two singlets, as the 1BC NMR confirms.
Problem 112 IR Spectrum 4000 3000 2000 1600 1200 V (cm) Mass Spectrum uv Spectrum 100 A,s. 265 nm (log10ε 2.6) λ max 271 nm 0og10ε 2.6 ) M* 150 solvent: methanol 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100.0 MHz, CDC, solution) 24 20 ppm 24 proton decoupled 200 160 120 80 40 δ (ppm) H NMR Spectrum 400 MHz, CDC, solution) expansion 7.2 7.0 ppm 0 δ (ppm) 10 8 6 5 2
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( s( 3ツ 922 3 S122 nan 2.

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