25) Using Hess's Law, find the ΔGrxn for: 2N2(g) + 502(8)2N2Os(g) Given: H2(g)2(8)H20(0) N05(g) +...
show steps • What is the AH for the reaction: 2N2(g) + 502(9) -> 2N205 H2(g) + 12 Oz(9) -> H20(1) AH = -285.8 kJ N2O3(9) + H20 (1) -> 2HNO3 (1) AH = -76.6 kJ N2(g) + 302(g) + H2(g) -> 2HNO3 (1) AH = -348.2 kJ Click to add notes
(D) SNU29) + 12 + 2HNO3(14) + NU19) 8) Determine the overall reaction, using Hess's Law to calculate the enthalpy of the reactions from the reaction step mechanism. Step1: 300,(9) ► N269) + 02(g) AH = -99.6 kJ Step 2: H2O(l) → H2(g) + 02(9) AH; = +285.8 kJ Step 3: Hz(9) + N2(g) + 3 02(9) → 2 HNO3(aq) AH; = -414.8 kJ Step 4: N2(g) + 02(9) ► NO(9) AH; = 90.2 kJ
Use Hess's law to determine A.Hº for the reaction C3H4(g) + 2 H2(g) -> C3H8(8), given that Hy(8) + O2(8) — H2O(1) A Hº = -285.8 kJ mol-1 C3H4(8) + 402(g) — 3 CO2(g) + 2 H2O(1) A Hº = -1937 kJ mol-1 C3H2(g) + 5O2(g) — 3CO2(g) + 4H2O(1) A Hº = -2219.1 kJ mol-1
12. Use Hess's Law to find AH for this reaction. (5) NO2(g) +2H2(g) ---> 2H2O(e) + NHs(g) Given the following two equations: 2NH3(g) -->N2(g) + 3H2(g) AHo +92 kJ 2N2(g)+ 2H2O(l) ---> NO2(g) + 2H2(g) AH° = +170 kJ
Calculate the enthalpy of the reaction 2NO(g) + O2(g)2NO2(g) Hess's law states that "the heat released or absorbed in a chemical process is the same whether the process takes place in one or in several steps." It is important to recall the following rules: given the following reactions and enthalpies of formation: 1. ¢ N2(g) + O2(g)+NO2(g), AH; = 33.2 kJ 2. N2(g) + O2(g) NO(g), AHB = 90.2 kJ 1. When two reactions are added, their enthalpy values are...
Hess's Law (b) Given the following thermochemical data: 2HNO3(aq) +A920(s) - H2O(1) +2AgNO3(aq) AH = -44.8 kJ Ag20(s) - 2Ag(s) + 1/2O2(9) AH = 31.0 kj H20(1) - H2(9)+1/202(9) AH = 285.8 kJ Use Hess's Law to determine AH for the reaction: Ag(s)+HNO3(aq) → 12H2(9)+AgNO3(aq) AH =
Hess's Law Given the following data: C2H2(g) + 5/202(9) + 2002/9) + H20(1) AH' = -1300.0 kJ CO2(g) + C(s) + O2(g) AH° = 393.5 kJ 2C(s) + H2(g) C2H2(g) AH° = 227.0 kJ Calculate AH for the reaction H2(g) + 1/202(9) — H20(1) Submit Answer Tries 0/5
Hess's Law problem, find change in heat 2NH3 + 1/2O2 --> N2H4 + 3H2O broken into 1. NH3 + 3N2O --> 4N2 + 3H2O 2. N2O + 3H2 --> N2H4 + H2O 3. N2H4 + O2 --> N2 + 2H2O 4. H2 + 1/2O2 -- H20
23. (6 points) Use Hess's law to calculate ΔG.xn using the following information. 2 03(g) -3 02(g) 02(g)-2 0(g) NO(g) + O3(g)--NO2(g) + O2(g) (6 points) Calculate ΔGrxn at 25 °C when P(NO) 0.015 atm, P(O)-0.76 atm, and P(NO2) atm. Is the reaction more or less spontaneous under these conditions? 0.42 -
2. Given the following data: H2O(l) → H2(g) + 1/2O2(g) ΔH° = 285.8 kJ 2HNO3(l) → N2O5(g) + H2O(l) ΔH° = 76.6 kJ 2N2(g) + 5O2(g) → 2N2O5(g) ΔH° = 28.4 kJ Calculate ΔH° for the reaction: 1/2N2(g) + 3/2O2(g) + 1/2H2(g) → HNO3(l) Note that you should be able to answer this one without needing to use any additional information from the thermo table. I've attempted this question multiple times. I am able to get to the simplified eqaution...