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The component of the external magnetic field along the central axis of a 125-turn circular coil of radius 26.0 cm decrsases f

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Answer #1

The induced emf is given as

Emf = -N *d(BA) / dt

where BA is equal to magnetic flux

Emf = -125 *pi*0.262 * (0.650 - 2.40) / 3.50

Emf = 13.27 V

so,

induced current, I = E/R

I = 13.27 / 9

I = 1.4748 A

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