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C5: Problem 6 Previous Problem Problem List Next Problem (1 point) Your task is to design a rectangular industrial warehouse

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Answer #1

1)

total cost =87(L+L+W+W+W+W)
=>total cost =87(2L+4W)

allocated $ 93960

=>87(2L+4W)=93960
=>174(L+2W)=93960
=>L+2W=540
=>L=540-2W

total area ,A(L,W)=LW
=>A(W)=(540-2W)W
=>A(W)=-2W2+540W
=>A'(W)=-2(2)W2-1+540(1)
=>A'(W)=-4W+540
=>A''(W)=-4(1)+0
=>A''(W)=-4

for maximum total area ,A'(W)=0,A"(W)<0

=>-4W+540=0
=>4W=540
=>W=135

A''(135)=-4
=>A''(135)<0

L=540-2W ,W=135
=>L=540-2(135)
=>L=540-270
=>L=270

therefore the dimensions for the maximum total area are
length L=270 feet
width W =135 feet

=====================================

2)

area of each of 3 compartments
LW 270 * 135 12150

each of 3 compartments has area of  12150 square feet

PLEASE RATE IF HELPFUL.PLEASE COMMENT IF YOU HAVE ANY DOUBT

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