Solution:
Molar solubility = Solubility in g L-1 / Molar mass
Molar mass of silver sulphate (Ag2SO4)= 311.80 g/mol
Therefore, molar solubility = 4.7 g L-1 / 311.80 g mol-1
=0.01507 mol /L = 0.01507 M
Ag2SO4 is dissociated as,
Ag2SO4 = 2Ag+ + SO4^2-
Ksp = ( 2S)^2 x S =4S^3
Ksp = 4 x (0.01057)^3
Ksp = 4.64 x 10^-6
The solubility of silver sulfate is 4.7 g/L. What is the Ksp of silver sulfate? Please see Molar ...
The solubility of silver sulfate is 4.7 g/L. What is the Ksp of silver sulfate? Please see Molar Solubility and Ksp for assistance. 402
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