SOLUTION
Machine (time in Min) | Profit per unit | ||||
Component | Shaper | Grinder | Min Units | Max Units | |
1 | 6 | 4 | 600 | 1000 | $8 |
2 | 4 | 5 | 1000 | $6 | |
3 | 4 | 2 | 200 | $9 | |
Total time (Hr) | 120 | 110 | |||
Total time (Min) | 7200 | 6600 |
Let C1 be the number of component 1 manufactured
C2 be the number of component 2 manufactured
C3 be the number of component 3 manufactured
So obejective function will be MAximise Z = 8C1 +6C2+9C3
Constraints:
Avaialbity of Hours of machine
6C1+4C2+4C3<=7200 ...For Shaper
4C1+5C2+2C3<=6600 ...For grinder
Component 1 has order of 600 and must be satisfied
Therefore C1>=600
No more than 200 units of component 3 can be sold
Therefore C3<=200
Upto 1000 units of component 1 and 2 can be sold
Therefore C1<=1000
C2<=1000
C1,C2,C3>=0 (Non negative)
So our LPP is
MAximise Z = 8C1 +6C2+9C3
Subject to
6C1+4C2+4C3<=7200
4C1+5C2+2C3<=6600
C1>=600
C3<=200
C1<=1000
C2<=1000
C1,C2,C3 >=0
Solution C1= 600 units
C2= 700 units
C3= 200 units
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Range is allowabe increase and allowable decrease
For C1, range is NA to 9 (8+1)
For C2, Range is 6 (6-0.667) to 9 (6+3) (5.33 not possible as C1 should be integer)
For C3, range is NA to 12(9+3)
Constraint | ||
R.H. Side | Range | |
7200 | 7440 | 4400 |
6600 | NA | 6300 |
600 | 1000 | 514.2857 |
200 | 900 | 100 |
1000 | NA | 600 |
1000 | NA | 700 |
Range = Constraint RHS + Allowable increase to Constraint RHS - Allowable decrease
D) If more time is available on grinder it will be worth 0 since shadow price is 0
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