Linear program is following:
Let X0, X1, X2, X3 be the number of Compact, Economy, Midsize and SUV models to be manufactured resp.
and P0, P1, P2, P3, P4 be the number of parts leftover of respective index number
Max 5000X0+6000X1+8000X2+10000X3-2P0-1.5P1-3P2-2.5P3-4.25P4
s.t.
2X0+1X1+4X2+6X3+P0 = 50000
4X0+4X1+5X2+5X3+P1 = 100000
4X0+5X1+6X2+1X3+P2 = 45000
1X0+1X1+1X2+1X3+P3 = 60000
4X0+3X1+6X2+12X3+P4 = 45000
X0,X1,X2,X3,P0,P1,P2,P3,P4 >= 0
Q6. (b) X0+X3 >= 10
where, X0 refers to number of Compact cars and X3 refers to SUVs
Q7. (d) X3 >= 2X0
Q8. (a) b1-(a1,0X0+a1,1X1+a1,2X2+a1,3X3) >= 3(b3-(a3,0X0+A3,1X1+A3,2X2+a3,3X3))
b1 is the current inventory of tires and b3 is the current inventory of steering wheels .
(a1,0X0+a1,1X1+a1,2X2+a1,3X3) represents the number of tires used. so remaining number of tires in ending inventory is b1-(a1,0X0+a1,1X1+a1,2X2+a1,3X3)
(a3,0X0+A3,1X1+A3,2X2+a3,3X3) represents the number of steering wheels used. so remaining number of steering wheels in ending inventory is b3-(a3,0X0+A3,1X1+A3,2X2+a3,3X3)
(there is an typo error in all the answer options, the question says tires should be 4 times, but in the answer options, 3 is written)
Q9. (c) f(x0,x1) = a0x0+a1a1+1
Q10. (d) f(x0,x1) = a0x2/x1 -a1x0+1
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