some sodium cyanide has been placed in a glass of orange juice to poison a secret agent the reaction is
CN-(aq) + H6H7O7(aq) -> HCN(g) + C6H7O7-(aq)
i) is this reaction an acid-base reaction?
ii) would this reaction generate enough HCN to poison the agent?
include the calculation of the equilibrium constant of the
reaction.
CN- Kb= 2.5e-5
HC6H7O Ka= 8.4e-4
i)
HC6H7O7 is acid as it donates H+ and forming C6H7O-
CN- is base as it is accepting H+ and forming HCN
So, the reaction given is acid-base reaction
Answer: yes
ii)
The reaction is:
CN-(aq) + HC6H7O7(aq) -> HCN(g) + C6H7O7-(aq)
Kc = [HCN][C6H7O7-] / [CN-][HC6H7O7]
= ([HCN][OH-]/[CN-]) * [C6H7O7-][H+]/[HC6H7O7] * 1/[H+][OH-]
= ([HCN][OH-]/[CN-][H+]) * ([C6H7O7-][H+]/[HC6H7O7]) * (1/[H+][OH-])
= Kb * Ka * 1/Kw
= (2.5*10^-5)*(8.4*10^-4)*1/(1.0*10^-14)
= 2.1*10^6
Answer: 2.1*10^6
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